The time period of a satellite revolving around the earth surface is,
\[T=2π\sqrt{\frac{(R+h)^3}{GM}}\;\;\text{or}\;\;T=\frac{2π}{R}\sqrt{\frac{(R+h)^3}{g}}\]
If the satellite is revolving away from the surface of the earth, $h$ will be more. So, the time period will be more. Hence, the satellite revolving away from the surface of the earth has longer period of revolution.