Let $t$ be the time required by the body to reach the maximum height $h$ when thrown upwards with a velocity $u$. At the maximum height, the velocity will be zero $v=0.$

\[v=u-gt\] \[0=u-gt\] \[\therefore t=\frac{u}{g}\]

If the velocity is doubled, then new velocity will be $u’=2u.$

Let $t’$ be the new time to reach the highest point. \[t’=\frac{u’}{g}=\frac{2u}{g}=2t\]

Thus, the new time required to reach the highest point will be twice the original time.

[Equations used above are deduced from Motion Under Gravity]

**SIMILAR QUESTIONS**

**Can an object have velocity and acceleration in perpendicular directions?**