# What is the angle of projection of a projectile for maximum horizontal range?

## OR: At what angle should a body be thrown so as to hit the most distant point?

Let a body be projected with velocity $u$ making an angle $\theta$ with horizontal. Then, the horizontal range $R$ is given by,

$R=\frac{u^2\sin2\theta}{g}$

The range $R$ will be maximum when $\sin2\theta=1$ $\sin2\theta=\sin90°$ $2\theta=90°$ $\therefore\theta=45°$

Hence, the angle of projection for maximum horizontal range is $45°.$